Re: how to implement a simple class forname?

From:

"Manuel" <mfc1981@gmail.com>

Newsgroups:

comp.lang.c++

Date:

19 Jul 2006 12:41:09 -0700

Message-ID:

<1153338069.212278.27040@m79g2000cwm.googlegroups.com>

Victor Bazarov wrote:

If I may... This sounds OK, only to take address of a member function
you need the class before the name:

     map["method1"] = &OneClass::method1;
     map["method2"] = &TwoClass::method2;

And when you call it, you can't prepend it with 'factory::'. You just
use

     map["method1"](parameters);

V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask

Of course, you may.

well. I think that this is not neccesary because in the end the methods
will be of the same class.

i make this:

FACTORY_H

typedef void (*PtrMethod)(std::vector<std::string>);

class Factory
{
    private:
        map<const char*, PtrMethod*, ltstr> theMap;

    protected:
        Factory();

        ~Factory();

                Object * method1(std::vector<std::string>);
                Object * method2(std::vector<std::string>);

    public:
                Object *
getObject(std::string,std::vector<std::string>);
};

FACTORY_CPP

Factory::Factory()
{
       map["method1"] = &method1;
       map["method2"] = &method2;
}

Object * Factory::getObject(string label,vector<string> paramaters)
{
        PtrMethod method = theMap[label];
        Object * object = (*method)(parameters);
        return energia;
}

is it correct? what do you think?

thank you very much by your attention