Re: mixing signed and unsigned

From:
"John Carson" <jcarson_n_o_sp_am_@netspace.net.au>
Newsgroups:
comp.lang.c++
Date:
Sun, 18 Feb 2007 20:34:40 +1100
Message-ID:
<45d81e3a$0$1152$61c65585@un-2park-reader-01.sydney.pipenetworks.com.au>
"John Harrison" <john_andronicus@hotmail.com> wrote in message
news:RFTBh.21441$Da4.5633@newsfe6-gui.ntli.net

Kai-Uwe Bux wrote:

John Harrison wrote:

I have a problem. I want to compare an integral value, n, against
three half open ranges as follows

[-A, 0) // range 1
[0, B) // range 2
[B, C} // range 3

Each range corresponds to a different outcome and if the integral
value isn't within any of the ranges, that's a fourth outcome. So
far so easy, the problem is that n is a signed quantity and A, B, C
are unsigned quantities. Apart from this obscure corner of my code
this makes perfect sense, so I don't want to change the signedness
of anything. How to I write these tests so that my code is reasonably
understandable, rather than a horrible mess of casts and compiler
warnings? One more point, of the unsigned quantity, only B is guaranteed
small
enough that it could be safely cast to a signed integer.


What about:

#include <iostream>

int main ( void ) {
  unsigned long A = 30;
  unsigned long B = 20;
  unsigned long C = 100;
  long x = 0;
  while ( std::cin >> x ) {
    if ( x >= 0 ) {
      if ( x < B ) {
        std::cout << "range 2";
      } else if ( x < C ) {
        std::cout << "range 3";
      } else {
        std::cout << "above all ranges";
      }
    } else {
      if ( ( -x ) <= A ) {
        std::cout << "range 1";
      } else {
        std::cout << "below all ranges";
      }
    }
    std::cout << '\n';
  }
}

This only compares positive values. As long as the unsigned type is
large enough to represent the absolute values of the signed type,
you will be fine.


I thought of something like that, but two problems.

-x would overflow if x == std::numeric_limits<ptrdiff_t>::min()


How about -(x+1) <= A-1? Executing this conditional on x being negative
looks OK to me.

--
John Carson

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