Re: Stroustrup, chapter 5, navigating arrays

From:
boguslaw.filipowicz@gmail.com
Newsgroups:
comp.lang.c++
Date:
7 Mar 2007 01:21:12 -0800
Message-ID:
<1173259272.194513.41260@t69g2000cwt.googlegroups.com>
The thing is that when you initialise an array that way, then it is
not automatically Null terminated. I mean it has exacly 3 elements.
You need add a 4th element to ensure only 3 elements will be printed
out. See below.

------------------- PROGRAMME --------------------------
#include <iostream>

void print_array(char ar[])
{
  std::cout << "printing elements:";
  for(char* p=ar; *p !=0; p++)
    std::cout << *p << "\t";

  std::cout << "\n";

}

int main() {

    char v1[] = { '1', '2', '3', '\0' };
    char v2[] = { 'a', 'b', 'c', '\0' };

  print_array(v1);
  print_array(v2);

}

------------------- OUTPUT -----------------------------------
[arch@voodo cpp]$ ./a.out
printing elements:1 2 3 ? ? ?
? H ? ? ? ? G ? ??
? ? ? @ ? H ?
? ? ? G ? ?
printing elements:a b c 1 2 3
? ? ? ? H ? ? ? ?G
? ? ? ? ? ? @ ?
        H ? ? ? ? G ??
[arch@voodo cpp]$

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