Re: Finding a program argument

On Apr 9, 3:15 am, "Jason Heyes" <jasonhe...@optusnet.com.au> wrote:


argv is an array of pointers (char*), not an array of strings
try loading the parameters in a container and then iterate through it.
A std::vector of std::string is perfect for the job.

int main(int argc, char* argv[])
{
  std::vector<std::string> vs;
  for(int n = 0; n < argc; ++n)
  {
    std::cout << "argument " << n;
    std::cout << " is ";
    std::cout << argv[n] << std::endl;
    vs.push_back(argv[n]);
  }

  typedef std::vector<std::string>::iterator VIter;
  VIter viter = std::find(vs.begin(), vs.end(), "-v");
  if(viter != vs.end())
  {
    std::cout << "parameter -v found\n";
  } else {
    std::cout << "parameter not found\n";
  }

  return 0;
}

/*
argument 0 is ./proj_test
argument 1 is -a
argument 2 is -b
argument 3 is -v
parameter -v found
*/