Re: Problem with C++ vectors

From:
Salt_Peter <pj_hern@yahoo.com>
Newsgroups:
comp.lang.c++
Date:
19 Apr 2007 09:52:08 -0700
Message-ID:
<1177001528.377279.31830@l77g2000hsb.googlegroups.com>
On Apr 19, 8:38 am, vasi...@gmail.com wrote:

I am surprised to see the output of the following C++ program using
vectors. The program is so simple. An element is pushed in a vector
"v" and the pointer to this element is obtained as "ptr_v". Then an
other element is pushed in the vector and after that the pointer
"ptr_v" to the earlier element is lost!!!


As expected. Although its not lost. Your code lost it - yes.
The vector has member functions begin(), front(), back() and end()
that will return corresponding iterators.

Whereas in case of array, the pointer to already stored element is
preserved even if you insert elements to that array. You can try
running this simple program and see the output.

The "ptr_v" addressing the 1st element of vector loses it's value when
an other element is inserted in the vector!


Why does that surprise you? Is std::vector not dynamic?

Did you not know that:
  std::vector< int > v(40);
generates a container of 40 default initialized elements?
yet its still a dynamic container?
  std::vector< int > v(40, 99);
generates the same with whatever initialized integer value you choose
(other than 99)?
  std::vector< std::string > vs(1000, "default string"); // what the
hell?

Why does this happen??? Any expert of C++ data structures can explain?

//
*****************************************************************************************
#include <iostream>
#include <vector>
using namespace std;

int main(int)
{

   vector<int> v;

   v.push_back(40);
   int *ptr_v;
   ptr_v = &v.at(0);
   cout<<"Value = "<<*ptr_v<<endl;
   cout<<"Adress of ptr is "<<ptr_v<<endl;
   v.push_back(98);

   cout<<"Adress of ptr is still "<<ptr_v<<endl;
   cout<<"Value = "<<*ptr_v<<endl;

//*************************************
   cout<<"......Now for array......"<<endl;

   int array[10];
   array[0] = 40;
   int *ptr_array;
   ptr_array = &array[0];
   cout<<"Value = "<<*ptr_array<<endl;
   cout<<"Adress of ptr is "<<ptr_array<<endl;
   array[1] = 98;
   cout<<"Adress of ptr is still "<<ptr_array<<endl;
   cout<<"Value = "<<*ptr_array<<endl;

   return 0;}

//
********************************************************************************************

Thanks
Waseem

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