Re: why does this call the destructor?

Hi All,

I have written the following to illustrate a problem.
I know I have some magic numbers etc please ignore them.
What I do not follow is why the line marked results in a call to the
destructor for the object.

Can someone please explain it for me?

#include <iostream>
#include <fstream>

using std::ostream;

class someClass {
    private:
    char *str;
    public:
    someClass();
    ~someClass();
    friend ostream& operator <<(ostream& lhs, someClass rhs);

};

someClass::someClass(){
    str = new char[10];
    strcpy(str, "something");

}

someClass::~someClass(){
    std::cout << "\nIn someClass destructor...\n";
    delete str;

}

ostream& operator <<(ostream& lhs, someClass rhs){
    lhs << rhs.str; // This results in a call to the destructor for
the someClass object....why?
    return lhs;

}

int main(){
    someClass soc;
    std::cout << soc;

}

Thanks for your help

Regards

Michael