Re: function pointers
In article <1182283434.863580.316930@g4g2000hsf.googlegroups.com>,
ender <astrothayne@gmail.com> wrote:
why can't the new operator be used on function pointers?
Can you post an example of what you are trying to do?
maybe I have the syntax wrong but when I tried creating a vector of
the form vector< int (*)(window, unsigned int)> I got a compile time
error stating that new could not be used on int (*)(window, unsigned
int). perhaps I am just ignorent of the correct way to pass a
function pointer type as a template argument (or use it in a
typedef). If that is the cause could you tell me the correct syntax?
try this it should produce 0 1 2 3 on separate lines:
#include <vector>
#include <iostream>
#include <algorithm>
typedef int (*PF)(int);
int foo(int x) { return x;}
struct bar
{
int x;
bar():x(0){}
void operator () (PF f)
{
std::cout << f(x++) << '\n';
}
};
int main()
{
std::vector<PF> vec;
for(int i=0;i!=4;++i)
vec.push_back(foo);
std::for_each(vec.begin(),vec.end(),bar());
}
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