Re: Dereferencing (pointer to) iterator

From:

"xgngli@gmail.com" <xgngli@gmail.com>

Newsgroups:

comp.lang.c++

Date:

Fri, 22 Jun 2007 19:30:09 -0700

Message-ID:

<1182565809.415233.272070@k79g2000hse.googlegroups.com>

On Jun 22, 6:04 pm, Andre Kostur <nntps...@kostur.net> wrote:

"xgn...@gmail.com" <xgn...@gmail.com> wrote innews:1182549317.833678.206870@z28g2000prd.googlegroups.com:

Suppose we have a vector:
vector<int> vec(10);

We can declare a iterator this way:
vector<int>::iterator vecItor;

and then dereference it like this:
for (vecItor = vec.begin(); vecItor != vec.end(); vecItor++)
{
cout << *vecItor << endl;
}

But how can we dereference the iterator if we declare it this way:
vector<int>::iterator* vecItor;

**vecItor.

That's a pointer-to-iterator. So you need to dereference your pointer
part, then dereference the iterator.

Thanks guys. That makes perfect sense. However, when I run this in
Visual Studio,

    vector<int> vec(10);
    vector<int>::iterator* vecItor = new vector<int>::iterator();

    for (*vecItor = vec.begin(); *vecItor != vec.end(); vecItor++)
    {
        cout << **vecItor << endl;
    }

it caused debug assertion failure: vector iterators incompatible.

So I suspect there is no problem with the grammar. I just need to
search somewhere else to
find a way making VS happy.