Re: Simple Tree Syntax Error

From:
 Travis <travis.bowers@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Tue, 26 Jun 2007 20:03:54 -0000
Message-ID:
<1182888234.586296.141870@p77g2000hsh.googlegroups.com>
On Jun 26, 12:15 pm, Kai-Uwe Bux <jkherci...@gmx.net> wrote:

Travis wrote:

I'm creating a real simple tree. No sorting and every node can have
infinite children.

// TreeNode.h

#ifndef TREENODE_H
#define TREENODE_H

#include <iostream>
#include <iomanip>
using namespace std;

// forward declare the tree class
template< class NODE_TYPE > class Tree;

// template definition of tree node
template< class NODE_TYPE >
class TreeNode
{
// be friends with the tree class
friend class Tree< NODE_TYPE >;

private:
    typedef TreeNode<NODE_TYPE> Node;


Right now, you are within the template TreeNode. Thus, the identifier
TreeNode already is a shorthand for TreeNode<NODE_TYPE>. There is no need
to abbreviate that any further.

// can have infinite children
std::vector<int> children;


Don't you mean:

  std::vector< TreeNode* > children;

    NODE_TYPE data;

public:
// constructor
TreeNode( const NODE_TYPE &d ) : data(d)
    {
        // allocate memory for children nodes
        //children = new std::vector<TreeNode< NODE_TYPE > *>;


Now this is going to be the trick part.

    }

    // accessor
    NODE_TYPE getData() const
    {
        return data;
    }
};

#endif

That is the declaration for my tree node. G++ keeps saying
std::vector<int> children; has a syntax error. Sure enough if I
comment the line out, everything compiles. I'm going nuts though
trying to figoure out the error, I dont see it.


What is a vector of integers supposed to do for you?

Best

Kai-Uwe Bux


I switched it to INTs to make sure it wasn't a problem with me using
TreeNode< NODE_TYPE > *>. I just forgot to change it back before
pasting it here. Thank you though.

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