Re: convert string into an array

From:
"BobR" <removeBadBobR@worldnet.att.net>
Newsgroups:
comp.lang.c++
Date:
Thu, 05 Jul 2007 01:38:52 GMT
Message-ID:
<MYXii.146175$Sa4.57872@bgtnsc05-news.ops.worldnet.att.net>
James Kanze <james.kanze@gmail.com> wrote in message...

/* """

On Jul 3, 10:46 pm, "Jim Langston" <tazmas...@rocketmail.com> wrote:

I would use a stringstream.


Just curious, but why a stringstream, and not an istringstream?

    [...]

    std::string str_array = "{201,23,240,56,23,45,34,23}";
    std::stringstream Buffer;
    Buffer << str_array;


Why those two lines, instead of simply:

    std::istringstream Buffer( str_array ) ;

""" */

Aww, c'mon James, we can do better than that. :-}

My original code, revised.
{
  std::string stin( "{201,23,240,56,23,45,34,23}" );

  std::istringstream in( stin.substr( 1, stin.size()-2 ) ); // <---- :-}
   // assumes the strings are always *that* format, "{....}".

  // now use this, or Jim's code from here ( with 'Trash' removed! [1]).
  std::vector<int> array;
  for( std::string line; std::getline( in, line, ',' ); ){
       std::istringstream conv( line );
       int num(0);
       conv >> num;
       if( not conv ){ break;}
       array.push_back( num );
       // conv.clear(); conv.str("");
       }
  for( std::size_t i(0); i < array.size(); ++i ){
       std::cout<< array.at( i ) <<" ";
       }
}
// output:201 23 240 56 23 45 34 23

[1]
// > Buffer >> Trash; // Throw away (
  char tst = Buffer.peek();
  if( tst == '{' || tst == ',' || tst == '}' ){ Buffer.ignore(1); }

--
Bob R
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