Re: Template-based database library?

From:
Andrew <Andrew.Selivanov@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Fri, 21 Sep 2007 08:47:43 CST
Message-ID:
<1190357290.537146.29880@r29g2000hsg.googlegroups.com>
On Sep 18, 10:02 pm, Gerhard Menzl <clcppm-pos...@this.is.invalid>
wrote:

Database-related libraries are conspicuously absent from Boost. Does
anyone know of a template-based, open source, relational database
library that supports the representation of arbitrary relations with
compile-time type safety? Or has such an achievement been found to be
impossible?

I am not looking for a solution that works out of the box (although this
would certainly be nice), but a solid concept that would spare me from
running into too many dead-ends would be welcome.

--
Gerhard Menzl

Non-spammers may respond to my email address, which is composed of my
full name, separated by a dot, followed by at, followed by "fwz",
followed by a dot, followed by "aero".


Take a look at Boost.MultiIndex:
http://www.boost.org/libs/multi_index/doc/examples.html
It has foreign keys support and some other features.

For example:

/* Boost.MultiIndex basic example.
 *
 * Copyright 2003-2005 Joaqu n M L pez Mu oz.
 * Distributed under the Boost Software License, Version 1.0.
 * (See accompanying file LICENSE_1_0.txt or copy at
 * http://www.boost.org/LICENSE_1_0.txt)
 *
 * See http://www.boost.org/libs/multi_index for library home page.
 */

#if !defined(NDEBUG)
#define BOOST_MULTI_INDEX_ENABLE_INVARIANT_CHECKING
#define BOOST_MULTI_INDEX_ENABLE_SAFE_MODE
#endif

#include <boost/multi_index_container.hpp>
#include <boost/multi_index/member.hpp>
#include <boost/multi_index/ordered_index.hpp>
#include <algorithm>
#include <iostream>
#include <iterator>
#include <string>

using boost::multi_index_container;
using namespace boost::multi_index;

/* an employee record holds its ID, name and age */

struct employee
{
  int id;
  std::string name;
  int age;

  employee(int id_,std::string name_,int
age_):id(id_),name(name_),age(age_){}

  friend std::ostream& operator<<(std::ostream& os,const employee& e)
  {
    os<<e.id<<" "<<e.name<<" "<<e.age<<std::endl;
    return os;
  }
};

/* tags for accessing the corresponding indices of employee_set */

struct id{};
struct name{};
struct age{};

/* see Compiler specifics: Use of member_offset for info on
 * BOOST_MULTI_INDEX_MEMBER
 */

/* Define a multi_index_container of employees with following indices:
 * - a unique index sorted by employee::int,
 * - a non-unique index sorted by employee::name,
 * - a non-unique index sorted by employee::age.
 */

typedef multi_index_container<
  employee,
  indexed_by<
    ordered_unique<
      tag<id>, BOOST_MULTI_INDEX_MEMBER(employee,int,id)>,
    ordered_non_unique<
      tag<name>,BOOST_MULTI_INDEX_MEMBER(employee,std::string,name)>,
    ordered_non_unique<
      tag<age>, BOOST_MULTI_INDEX_MEMBER(employee,int,age)> >

employee_set;


template<typename Tag,typename MultiIndexContainer>
void print_out_by(
 const MultiIndexContainer& s,
 Tag* =0 /* fixes a MSVC++ 6.0 bug with implicit template function
parms */
)
{
  /* obtain a reference to the index tagged by Tag */

  const typename
boost::multi_index::index<MultiIndexContainer,Tag>::type& i=
    get<Tag>(s);

  typedef typename MultiIndexContainer::value_type value_type;

  /* dump the elements of the index to cout */

 
std::copy(i.begin(),i.end(),std::ostream_iterator<value_type>(std::cout));
}

int main()
{
  employee_set es;

  es.insert(employee(0,"Joe",31));
  es.insert(employee(1,"Robert",27));
  es.insert(employee(2,"John",40));

  /* next insertion will fail, as there is an employee with
   * the same ID
   */

  es.insert(employee(2,"Aristotle",2387));

  es.insert(employee(3,"Albert",20));
  es.insert(employee(4,"John",57));

  /* list the employees sorted by ID, name and age */

  std::cout<<"by ID"<<std::endl;
  print_out_by<id>(es);
  std::cout<<std::endl;

  std::cout<<"by name"<<std::endl;
  print_out_by<name>(es);
  std::cout<<std::endl;

  std::cout<<"by age"<<std::endl;
  print_out_by<age>(es);
  std::cout<<std::endl;

  return 0;
}

--
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