Re: Addressing a &vector<>[i] as a C-array & the C++ standard.

 From the C++-FAQ Lite:

http://www.parashift.com/c++-faq-lite/containers.html#faq-34.3

----------------------------
34.3] Is the storage for a std::vector<T> guaranteed to be contiguous?
Yes.

This means you the following technique is safe:

  #include <vector>
  #include "Foo.h" /* get class Foo */

  // old-style code that wants an array
  void f(Foo* array, unsigned numFoos);

  void g()
  {
    std::vector<Foo> v;
    ...
    f(v.empty() ? NULL : &v[0], v.size()); ? safe
  }

The funny expression v.empty() ? NULL : &v[0] simply passes the NULL
pointer if v is empty, otherwise passes a pointer to the first (zeroth)
element of v. If you know a priori that v is not empty, you can change
that to simply &v[0].
----------------------------

I can find nothing in the standard to justify this statement. Does
anyone know the section in the standard (if any) which justifies this
statement?