Re: divide all elements in a vector by a number

From:
utab <umut.tabak@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 15 Nov 2007 10:51:06 -0800 (PST)
Message-ID:
<6bcc3d55-1558-481a-9652-10576331aeaa@b15g2000hsa.googlegroups.com>
On Nov 15, 6:01 pm, "Victor Bazarov" <v.Abaza...@comAcast.net> wrote:

utab wrote:

Dear all,

I was wondering if I could divide all elements of a vector by the max
element of that vector.

I checked the STL references and found transform, for_each and lately
BOOST_FOREACH, but transform and for_each algorithms are not suited
since I have another argument to supply to the functions, namely
max_element. I wondered if this is possible or not through the
standard.

BOOST_FOREACH seemed the best option to me. But I wondered :)


Everybody is supposed to do their own homework.

V
--
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Oops, you are not right since I did not paste any code :)

#include <iostream>
#include <vector>
#include <algorithm>

using namespace std;

void print(double d)
{
    cout << " " << d << endl;
}

int main()
{
     vector<double> x;
     for(double i=0;i!=10;++i)
       x.push_back(i);

     double max=*max_element(x.begin(),x.end());

     cout << max << endl;

     vector<double>::iterator iterx=x.begin();
     for(;iterx!=x.end();++iterx)
     {
       if(fabs(max)>1e-6){ // just a pre-caution for divide by 0.
         *iterx=*iterx/max;
       }
     }
     for_each(x.begin(),x.end(),print);

     return 0;
}

That was the question, without a loop, is this possible?
I could not find the answer in my references,
I made the example quickly, hope it is error free!
Rgds,

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