Re: Can I avoid the use of arrays in this situation or do I have to
use them?
On Nov 25, 5:37 am, terminator <farid.mehr...@gmail.com> wrote:
<snip>
turninng debug switch off I found the following two sequences almost
equivalent in time:
1.vector buf ; swap ;
2. array buf ; fill ; result.reserve ; copy ;
#include <iostream>
#include <conio.h>
#include <vector>
#include <string>
#include <Ctime>
using namespace std;
enum {sz=1000,loop=100*1000};
void vec1(){
vector <int> v(sz),dest;
v.swap(dest);
}
void vec0(){
vector <int> v,dest;
v.reserve(sz);
fill(v.begin(),v.begin()+v.capacity(),0);
v.swap(dest);
}
void vec2(){
vector <int> v(sz),dest;
swap(dest,v);
}
void arr(){
int arr[sz];
vector <int> dest;
fill(arr,&(arr[sz]),0);
dest.reserve(sz);
copy(arr,&arr[sz],dest.begin());
}
template <typename pred>
void test(pred f,string txt){
cout<<("testing:"+txt)<<endl;
const clock_t c=clock();
for(int i=0;i<loop;i++)
f();
cout<<clock()-c<<" ms"<<endl;
}
int main()
{
vector<A> v1(sz);
cout << "\nvector * i=" << A::get() << endl ;
A::get()=0;
vector<A> v2;
v2.reserve(sz);
cout << "reserve * i=" << A::get() << endl ;
test(vec0,"reserve");
test(vec1,"vector");
test(vec2,"std::swap");
test(arr,"array");
getch();
return 0;
}
output:
testing:reserve
1172 ms
testing:vector
1141 ms
testing:std::swap
1125 ms
testing:array
1141 ms
regards,
FM.
I noticed however in even the "array" routine
a vector is created. Have you tried one where
there are _no_ vectors created in the routines?
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