Re: Vector erase dumps core when vector size is 2

From:
"Howard" <me@here.com>
Newsgroups:
comp.lang.c++
Date:
Wed, 5 Dec 2007 15:16:35 -0800
Message-ID:
<GtOdnekkEt_PrMranZ2dnUVZ_jSdnZ2d@comcast.com>
"Anil" <anil.pundoor@gmail.com> wrote in message
news:ca663000-10df-4d97-8c40-4f203820eea9@w40g2000hsb.googlegroups.com...

I am facing problem while erasing an elemet from stl vector when its
size is 2. It works fine when SIZE > 2.
Can anybody help me in this?? Following is the sample code which i
tried.

#include <iostream>
#include <vector>

using namespace std;
#define SIZE 2
main()
{
  vector<int> myVect;
  std::vector<int>::iterator iter;

  for(int i =0; i<SIZE; i++)
   myVect.push_back(i);

  cout<< myVect.size() << "\n";
  for( iter = myVect.begin(); iter != myVect.end(); iter++)
     cout<< *iter << " ";

  cout<<"\n";

  for( iter = myVect.begin(); iter != myVect.end(); iter++)
  {
     cout<< *iter << "\n";
    if( *iter == 1)
        myVect.erase(iter);

  }

return 0;
}


I think that calling erase above causes iter to become invalidated, so it's
illegal to call iter++ on it afterwards, regardless of whether it seems to
work on some vectors. The erase functions returns an iterator to the next
item, so you can set iter to that when calling erase, and only incrementing
when not calling erase. I believe there's also a std algorithm for this
(remove_if or something like that, I forget).

-Howard

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