Re: There is no "continue" for switch?

From:

Paul Brettschneider <paul.brettschneider@yahoo.fr>

Newsgroups:

comp.lang.c++

Date:

Tue, 18 Mar 2008 23:42:40 +0100

Message-ID:

<89760$47e04560$5470058e$8603@news.chello.at>

Paul Brettschneider wrote:

xz wrote:

What if I want the following:

vector<int> v;

// v is loaded by push_back()

switch( v.size() ) {
case 2:
//do something

case 4:
//somehow delete two element
//and then do the same thing as in case 2

case 6:
//somehow delete two element
//and then do the same thing as in case 4

default:
//...
}

I thought using "continue" to implement this but got this:

continue statement not within a loop

Of course there is a continue for switch (for your example else-thread):

#include <iostream>

void f(uint8_t n)
{
        std::cout << n << '\n';
        switch(n) {
                for(;;) {
                case 2:
                        std::cout << "do_something\n";
                        break;
                case 4:
                        std::cout << "somehow delete 2 elements\n";
                        continue;
                case 6:
                        std::cout << "somehow delete 4 elements\n";
                        continue;
                default:
                        std::cout << "default\n";
                        break;
                }
        }
}

int main()
{
        f(2);
        f(4);
        f(6);
        f(1);
}

Of course this doesn't do what you what it to do - it doesn't recompute
the label to jump to. Sorry, I'm tired.

Here is the correct solution (I think):

#include <iostream>

void f(int n)
{
        std::cout << n << '\n';
        for(;;) {
        switch(n) {
                case 2:
                        std::cout << "do_something\n";
                        break;
                case 4:
                        std::cout << "somehow delete 2 elements\n";
                        n -= 2;
                        continue;
                case 6:
                        std::cout << "somehow delete 4 elements\n";
                        n -= 4;
                        continue;
                default:
                        std::cout << "default\n";
                        break;
        }
        break;
        }
}

int main()
{
        f(2);
        f(4);
        f(6);
        f(1);
}