Re: std::list wrapper (+templates)

template <class T>
class List {
public:
    List();
    List(const List&);
    List(int, const T&);

    void push_back(const T &);
    void push_front(const T &);
    void pop_back();
    void pop_front();
    void remove(const T &);
    int size();

    friend std::ostream &operator<<(std::ostream &out, const List<T> &);

private:
    std::list<T> *lst;
};

template <class T>
List<T>::List() { lst = new std::list<T>(); }

template <class T>
List<T>::List(const List &rhs) { lst = new std::list<T>(rhs.lst); }

template <class T>
List<T>::List(int n, const T& value) { lst = new std::list<T>(n,
value); }

template <class T>
void List<T>::push_back(const T& value) { lst->push_back(value); }

template <class T>
void List<T>::push_front(const T& value) { lst->push_front(value); }

template <class T>
void List<T>::pop_back() { lst->pop_back; }

template <class T>
void List<T>::pop_front() { lst->pop_front; }

template <class T>
void List<T>::remove(const T& value) { lst->remove(value); }

template <class T>
int List<T>::size() { return (int)lst->size; }

template <class T>
std::ostream &operator<<(std::ostream &out, const List<T> &L)
{
    for (std::list<T>::iterator it = L.lst->begin(); it != L.lst->end(); +
+it)
        out << " " << *it;

    out << std::endl;
    return out;
}

int main()
{
    List<int> il;

    for (int i = 0; i < 10; ++i)
        il.push_back(i);

    std::cout << il;

    return 0;
}

There's a crazy problem with operator>> MSVS6 says that 'lst' is
undeclared... I'm astounded... GNU G++ says that 'it' (the iterator in
operator>>) is not declared in this scope..