Re: best way to "delete" all objects in a std::vector.

From:

"jason.cipriani@gmail.com" <jason.cipriani@gmail.com>

Newsgroups:

comp.lang.c++

Date:

Tue, 3 Jun 2008 16:26:14 -0700 (PDT)

Message-ID:

<0419aa1b-8bea-4e99-8e04-7da830834732@i76g2000hsf.googlegroups.com>

On Jun 3, 5:23 pm, Daniel Pitts
<newsgroup.spamfil...@virtualinfinity.net> wrote:

I have std::vector<Base *> bases;

I'd like to do something like:
std::for_each(bases.begin(), bases.end(), operator delete);

Is it possible without writing an adapter? Is there a better way? Is
there an existing adapter?

What's wrong with:

for (std::vector<Base *>::iterator i = bases.begin(); i !=
bases.end(); ++ i)
  delete *i;

It's only two lines; and it's clear what is happening. I don't think
you'll be able to beat that. If it's something you do frequently you
could write a utility function like:

template <class T> void delete_all (T &cont) {
  typedef typename T::iterator iter_t;
  for (iter_t i(cont.begin()); i != cont.end(); ++ i)
    delete *i;
  cont.clear();
}

Example:

struct A { ... };

void f () {

  vector<A *> x;
  list<A *> y;
  set<A *> z;

  x.push_back(new A);
  x.push_back(new A);
  y.push_back(new A);
  y.push_back(new A);
  z.insert(new A);
  z.insert(new A);

  delete_all(x);
  delete_all(y);
  delete_all(z);

}

Jason