Re: How to return a pointer to an array?

From:
Salt_Peter <pj_hern@yahoo.com>
Newsgroups:
comp.lang.c++
Date:
Sat, 18 Oct 2008 06:40:36 -0700 (PDT)
Message-ID:
<caeded44-28d9-4ba2-8411-e850134de9bd@l64g2000hse.googlegroups.com>
On Oct 18, 7:56 am, mani <manigand...@gmail.com> wrote:

int (*nVar)[10]..This is the variable i used in a function.. i
tried ...nothing worked.. anyone please tell me how to return it....


Show minimum, compileable code please.
We don't know if what you have is a local array and a dangling
pointer.
Prefer const references. Prefer std::vector<> over fixed arrays.

#include <iostream>
#include <vector>
#include <algorithm>
#include <iterator>

template< typename T >
void foo( const std::vector< T >& r_v )
{
  std::copy( r_v.begin(),
             r_v.end(),
             std::ostream_iterator< T >(std::cout, " ") );
  std::cout << std::endl;
}

int main()
{
  std::vector< int > vn(10, 99);
  foo( vn );
}

/*
99 99 99 99 99 99 99 99 99 99
*/

The above should really be an operator<<
If you prefer working with dumb fixed arrays:

template< typename T, const std::size_t Size >
void bar( const T (& r_a)[ Size ] )
{
  for( std::size_t i = 0; i < Size; ++i)
  {
    std::cout << r_a[i];
    std::cout << " ";
  }
  std::cout << std::endl;
}

int main()
{
  int array[10] = { 0 };
  bar( array );
}

/*
0 0 0 0 0 0 0 0 0 0
*/

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