Re: Error compiling in g++ 4.1 and 4.3 (template and typedef)

From:
Lars Tetzlaff <lars.tetzlaff@gmx.net>
Newsgroups:
comp.lang.c++.moderated
Date:
Sun, 8 Feb 2009 14:56:08 CST
Message-ID:
<gmmdip$fg2$1@online.de>
afcmoraesf@gmail.com schrieb:

Hi,

  I'm getting the error

main.C: In constructor ?Test<T>::Test(T, T, T)?:
main.C:19: error: expected `;' before ?it?

compiling the code

=======BEGIN
#include <iostream>
#include <list>
#include <string>

template<class T> class Test
{
public:
     typedef std::list<T> T_LIST;
     Test(T a1, T a2, T a3);
};

template<class T> Test<T>::Test(T a1, T a2, T a3)
{
     T_LIST t_list;
     t_list.push_front(a1);
     t_list.push_front(a2);
     t_list.push_front(a3);

     T_LIST::iterator it;

     for ( it = t_list.begin() ; it != t_list.end() ; it++ )
         std::cout << *it << std::endl;
}

int main(int argc, char** argv)
{
     Test<int> test(1, 2, 3);
}
=====END

what's wrong ?

Thanks,
Antonio


gcc 4.3.2 complains;

t1.cpp: In constructor ?Test<T>::Test(T, T, T)?:
t1.cpp:19: error: expected `;' before ?it?
t1.cpp:21: error: ?it? was not declared in this scope
t1.cpp: In constructor ?Test<T>::Test(T, T, T) [with T = int]?:
t1.cpp:28: instantiated from here
t1.cpp:19: error: dependent-name ?std::list::iterator? is parsed as a
non-type, but instantiation yields a type
t1.cpp:19: note: say ?typename std::list::iterator? if a type is meant

So, inserting "typemname" in fornt of line 19 does the job.

Lars

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