Re: #include within namespace scope

From:
joecook@gmail.com
Newsgroups:
comp.lang.c++
Date:
Mon, 16 Feb 2009 07:47:41 -0800 (PST)
Message-ID:
<a7b9bd4e-3f28-4525-a102-94068bff6efc@b16g2000yqb.googlegroups.com>
On Feb 16, 10:18 am, joec...@gmail.com wrote:

On Feb 16, 9:10 am, p...@informatimago.com (Pascal J. Bourguignon)
wrote:

joec...@gmail.com writes:

Is there anything that prevents putting #include directives inside
namespace scope within the standard?


Nothing, but you will declare the stuff defined in the header inside
this namespace.

Let's say I have a (evil) header:


Therefore you have:

    namespace evil
    {
    #include <vector>
    using namespace std; // bad doggy

    class Doo
    {
    public:
     vector<int> d;
    };
    }
    int main()
    {
      // Nothing
    }

That is, you are using a class evil::std::vector<int>
Where is the implementation of this class?
Notice that libg++ only defines methods such as std::vector<int>::clear=

,

not evil::std::vector<int>::clear.


I expected the preprocessor to expand the include header at the
location I have put it.
I further expected that the compiler should always refer to ::std::
instead of std::, and therefore 'std' will not get caught inside the
namespace where it is not intended. Somewhere that expectation is
being broken, and I'm still not sure exactly where..
Joe C- Hide quoted text -

- Show quoted text -


To clarify,

 The standard states, "Whenever a name x defined in the standard
library is mentioned, the name x is assumed to be fully qualified
as ::std::x, unless explicitly described otherwise. For example, if
the Effects section for library function F is described as calling
library function G, the function ::std::G is meant."

  In this case, the compiler seems to be making the assumption that
include directives will always be at global scope, but I cannot find
any part of the standard that would back up such an assumption. That
is what I am searching for.

Thanks!
Joe C

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