Re: convert std:: vector of strings/doubles to arrays

puzzlecracker wrote:
 > In my case, I want to convert std::vector of names and std::vector of
 > values to char ** and double *

 > Please keep in mind that order of names and values matters and should
 > match.
 >
 > Thanks

Is it as simple? Or I did not understand something!
**names is almost the same as *names[] and *values is almost the same as
values[]. The little difference is the table / array a pointer
containing the address is a const pointer u cant "move" it

double * const values[] = {1.5, 3, 4.5};

so basically the program would be as below:

#include <iostream>
#include <vector>

using namespace std;

int main(int argc, char *argv[])
{
     vector<string> v_str;
     vector<double> v_dbl;
     v_str.push_back("aaa");
     v_str.push_back("bbb");
     v_str.push_back("ccc");
     v_str.push_back("ddd");
     v_dbl.push_back(1.5);
     v_dbl.push_back(3.0);
     v_dbl.push_back(4.5);

     // definition of arrays and filling them with vectors val
     char* names[v_str.size()];
     double values[v_dbl.size()];
     for(size_t i=0; i<v_str.size(); ++i) {
         // const_cast<double*> removes const given by c_str()
         // either u define names[] with const or keep
         // const_cast<double*>() here in order for the code to work.
         names[i] = const_cast<char*>(v_str[i].c_str());
     }
     for(size_t i=0; i<v_dbl.size(); ++i) {
         values[i] = v_dbl[i];
     }

     // end here is only checking that everything works fine
     for(size_t i=0; i<v_str.size(); ++i) {
         cout << names[i] << endl;
     }
     for(size_t i=0; i<v_dbl.size(); ++i) {
         cout << values[i] << endl;
     }

     return 0;
}