Re: Passing Temporaries to perform non const operations

From:
Bart van Ingen Schenau <Bart.van.Ingen.Schenau@ict.nl>
Newsgroups:
comp.lang.c++
Date:
Thu, 16 Apr 2009 00:03:06 -0700 (PDT)
Message-ID:
<a61f3058-b609-4153-b160-23ef01f744fa@o11g2000yql.googlegroups.com>
On Apr 15, 4:09 pm, joec...@gmail.com wrote:

Altering a temporary is perfectly legal, for example:

std::vector<int> vec(40);
std::vector<int>(4).swap(vec); //legal.

I am trying to get this same functionality, but within an assignment
operator, but can't seem to find a good way to bind the temporary.

For example:

class Foo;
int main()
{
 Foo f;
 f = Foo(20);

}

#include <vector>
class Foo
{
public:
  Foo(int size=0) { m_data.resize(size);}

  // PROBLEM HERE. The temporary can't be bound to a reference to no=

n-

const
  // But if this were 'const reference', the swap function could not
be called using it.
  void operator=(Foo& foo)
  {
    m_data.swap(foo.m_data);
  }
  std::vector<int> m_data;

};

The only work-around I could think of was this ugly code:
void operator=(const Foo& foo)
{
  std::vector<T>* tmpVec = const_cast<std::vector<T>*>(foo.m_data);
  tmpVec->swap(m_data);

}

Any better suggestions?


As long as move semantics are not yet available, your best option is
to use pass-by-value and hope the compiler optimises out any redundant
temporaries.

   void operator=(Foo foo)
   {
     m_data.swap(foo.m_data);
   }

Thanks,
Joe


Bart v Ingen Schenau

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