Re: how to specify overloaded function
On Jul 29, 6:45 am, "Amadeus W.M." <amadeu...@verizon.net> wrote:
I wan to do this:
#include <algorithm>
//
std::transform(Xj.begin(), Xj.end(), logXj.begin(), std::log);
//
where Xj and logXj are of type
class Foo
{
public:
typedef double * iterator;
typedef const double * const_iterator;
//
};
The compiler understandably gets confused by std::log, with the following
error:
fooMain.C:131: error: no matching function for call to =91transform(doubl=
e*,
double*, double*, <unresolved overloaded function type>)'
make: *** [main] Error 1
How do I specify that I want
double log(double) ?
Thanks!
Just add a cast to the overloaded type you desire:
#include <algorithm>
#include <vector>
#include <cmath>
#include <iostream>
using namespace std;
int main()
{
vector<double> x;
x.push_back(10);
std::transform(x.begin(),x.end(),x.begin(),(double (*)(double))
std::log);
cout << *x.begin();
}
// Prints: 2.30259
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