Re: std::vector of const values
Dave =D0=BD=D0=B0=D0=BF=D0=B8=D1=81=D0=B0=D0=B2(=D0=BB=D0=B0):
#include <vector>
#include <iostream>
void doStuff( const std::vector< const int* >& ints )
{
for( size_t i = 0; i != ints.size(); ++i )
std::cout << *ints[ i ] << std::endl;
}
int main()
{
int i1, i2, i3;
std::vector< int* > ints;
ints.push_back( &i1 );
ints.push_back( &i2 );
ints.push_back( &i3 );
doStuff( ints );
return 0;
}
However, it seems to me that, if the compiler wanted to, it could just
treat the argument as vector< const int* > and just proceed. So does
anyone know of a way to do that? Or am I stuck with making copies. Is
there some fundamental reason why a vector of non-const values could
not be treated as a vector of const values?
I propose to use iterators:
template <typename Iter>
void doStuff(Iter begin, Iter end)
{
for(Iter it = begin; it != end; ++it)
{
std::cout << **it << std::endl;
}
}
....
doStuff( ints.begin(), insts.end());
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