Re: std::vector error

From:
"Vladimir Grigoriev" <vlad.moscow@mail.ru>
Newsgroups:
microsoft.public.vc.language
Date:
Tue, 15 Dec 2009 18:20:28 +0300
Message-ID:
<u9jpXoZfKHA.5792@TK2MSFTNGP05.phx.gbl>
Victor, it is a good remark and I have presented already more detailed
information.

Vladimir Grigoriev

"Victor Bazarov" <v.Abazarov@comAcast.net> wrote in message
news:hg893g$ef5$1@news.datemas.de...

Vladimir Grigoriev wrote:

Having the following code

struct Point

{

    Point( int i = 0, int j = 0 ): x( i ), y( j ) {}

    int x, y;

};

#define MAX_SIZE 10

int _tmain(int argc, _TCHAR* argv[])

{

    std::vector<Point> v;


I don't see '#include <vector>' anywhere in this program. Did you post
the actual code?

    v.reserve( MAX_SIZE );

    for ( int i = 0; i < MAX_SIZE; ++i )

    {

        v.push_back( Point( i, i ) );

    }

    return 0;

}

I get the error

error C2446: ':' : no conversion from 'const
std::_Vector_iterator<_Ty,_Alloc>' to 'int'
        with
        [
            _Ty=Point,
            _Alloc=std::allocator<Point>
        ]
        No user-defined-conversion operator available that can perform
this conversion, or the operator cannot be called

 : while compiling class template member function
'std::_Vector_iterator<_Ty,_Alloc>
std::vector<_Ty>::insert(std::_Vector_iterator<_Ty,_Alloc>,const _Ty &)'
        with
        [
            _Ty=Point,
            _Alloc=std::allocator<Point>
        ]

The error occurs inside <vector> in this place

iterator insert(iterator _Where, const _Ty& _Val)

{ // insert _Val at _Where

size_type _Off = size() == 0 ? 0 : _Where - begin();

_Insert_n(_Where, (size_type)1, _Val);

return (begin() + _Off);

}

What is the matter?


Any chance you're using VC++ v6? If so, you're on your own.

I don't see you use 'insert' in your code anywhere. Are you sure you've
posted the code that you've compiled?

V
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