Vector of iterators?

From:
Rune Allnor <allnor@tele.ntnu.no>
Newsgroups:
comp.lang.c++.moderated
Date:
Thu, 11 Mar 2010 13:55:45 CST
Message-ID:
<9130a533-7926-49dc-9b0c-83dcd585717a@g4g2000yqa.googlegroups.com>
Hi all.

First of all: I *know* I am playing with fire with this one;
I just want to get some impression of how bad burns I'm risking.

I have an application that implements a Doubly Connected
Edge List (DCEL):

struct edge_t {
     size_t origin;
     size_t next;
     size_t previous;
     size_t inverse;
};

std::vector<point_t> points;
std::vector<edge_t> edges;

Starting from some edge, one traverses the data structure by
nested function calls. For instance, "the point at the origin of the
previous of the current edge's inverse edge" would be referred
to as something like

point_t p = points[edges[edges[edges[n].inverse].previous].origin];

where n is the indes of the current edge. This becomes very
messy very quickly, so I was wondering if it might be possible
to somehow implement the edge list in terms of iterators:

class edge_t;
typedef std::vector<point_t>::iterator pi_t;
typedef std::vector<edge_t>::iterator ei_t;

struct egde_t {
    pi_t origin;
    ei_t next;
    ei_t previous;
    ei_t inverse;
};

If so, it might be possible to simplify the above dereference
to something like

point_t p = *(n.inverse().prev().origin);

which is actually comprehensable to a human reader. I know
there are a lot of technical details that need to be addressed
(like if it is possible to define an iterator to a class that have
not
yet been declared, or how to do away with the iterator dereference
operator '*' internal to the expression), but leave those for now.

My question is: What are the dangers of inserting iterators
in collections? I am aware that the vector the iterator refers
to could do some internal reorganizations of memory, invalidating
stored iterators, but in this particular case memory requirements
are deterministic, and everything can be allocated and initialized
up front, never to (need to) change again for the duration of the
algorithm.

If (well, after) this idea has been torn apart by the experts - are
there other ways to simplify the semantics as indicated?

Rune

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