Re: Syntax Error

From:

"Thomas J. Gritzan" <phygon_antispam@gmx.de>

Newsgroups:

comp.lang.c++

Date:

Fri, 21 May 2010 21:11:26 +0200

Message-ID:

<ht6lsu$52s$1@newsreader5.netcologne.de>

Am 21.05.2010 21:00, schrieb Peter Olcott:

class FooListType {
  std::vector<FooType> Foos;
public:
  FooListType& operator+=( const FooListType& FooList );
  FooType& operator[](uint32 N){ return this->Foos[N]; };
  uint32 size(){ return Foos.size(); };

Make size a const function:

uint32 size() const { return Foos.size(); };

Also, add an const overload for operator[]. You can't call non-const
member functions on a const object or reference to const.

};

inline FooListType& FooListType::operator+=(const FooListType& FooList) {
  for (uint32 N = 0; N < FooList.size(); N++) // << Error is Here
    Foos.push_back(FooList[N]);
  return *this;
}

Points to line 11 above:
error C2662: 'FooListType::size' : cannot convert 'this' pointer from
'const FooListType' to 'FooListType &' Conversion loses qualifiers

What am I doing wrong here?

See above.
The function could also easier be implemented without a loop:

{
   // append elements of FooList.Foos to this->Foos
   Foos.insert( Foos.end(), FooList.begin(), FooList.end() );
   return *this;
}

--
Thomas