Re: Initialization of static anonymous-namespace members from a dynamically loaded lib

From:
"Alf P. Steinbach /Usenet" <alf.p.steinbach+usenet@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Sun, 09 Jan 2011 22:00:39 +0100
Message-ID:
<igd7rd$s0p$1@news.eternal-september.org>
* m0shbear, on 09.01.2011 21:56:

Given
// foo.cpp
#include<map>
namespace {
int init_s();
std::map<int,int> m;
int dummy = init_s();
int init_s() {
m[1] = 2;
m[5] = 4;
return 0;
}
};
// ...
int Foo::bar() {
return m[5];
}
// ...

// foo.h
class Foo {
//...
int bar();
// ...
};

If foo.o is linked at build time, the compiler automagically adds the
call to init_s() in the libc++ static init. But if it is dynamically
loaded, this condition is guaranteed to be satisfied. Or is it? I
don't want to waste memory by having an individual copy of supposedly
static data, yet I don't want UB from guessing and hoping.

Is it even possible to have file-scope non-POD statics upon whose
operations do not invoke UB, inside a d-l lib?


The C++ standard does not address or even acknowledge the existence of
dynamically loaded libraries except that one can interpret some wording about
delayed initialization as pertaining to dynamically loaded libraries.

Anyway, the short of it is that in Windows you can generally rely on techniques
such as above, but not in *nix.

Cheers & hth.,

- Alf

--
blog at <url: http://alfps.wordpress.com>

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