Re: function calls

From:
=?ISO-8859-1?Q?=D6=F6_Tiib?= <ootiib@hot.ee>
Newsgroups:
comp.lang.c++
Date:
Mon, 28 Feb 2011 14:20:12 -0800 (PST)
Message-ID:
<fd3e7076-47da-40f3-aa05-9a0cf5aeb42d@p11g2000vbq.googlegroups.com>
On Feb 28, 9:45 pm, "Paul" <pchris...@yahoo.co.uk> wrote:

" Tiib" <oot...@hot.ee> wrote in message

news:7e2e42b3-2410-443a-95c2-46f262c8334b@n18g2000vbq.googlegroups.com...
On Feb 25, 11:07 am, "Paul" <pchris...@yahoo.co.uk> wrote:

Please let me know if you still do not understand and I will re-explain
again.


--Your code does not work. You can not overwrite object 'Dog dog;' in a
--way that Cat's destructor is called for it when that dog leaves
--scope ... Dog's destructor is called for it on all C++ compilers i
--could reach. What destructor will be called is pre-decided and set
--already compile time. So it seems that you do not understand yourself
--what you are talking about.

#include <iostream>
class Animal{};
class Dog: public Animal{};
class Cat: public Animal{};

int main()
{
 Cat* p_cat = new Cat;
 std::cout<< p_cat << std::endl;
 delete p_cat;
 Dog* p_dog = reinterpret_cast<Dog*>(p_cat);
 p_dog = new Dog;
 std::cout << p_dog;

}


What does this code overwrite?
Also ... most compilers optimize the two lines:

  Dog* p_dog = reinterpret_cast<Dog*>(p_cat);
  p_dog = new Dog;

Into something like:

  Dog* p_dog = new Dog;

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