Re: Logic AND between some strings
On 08/03/2011 21:46, Paul wrote:
"Pete Becker" <pete@versatilecoding.com> wrote in message
news:2011030808444315377-pete@versatilecodingcom...
On 2011-03-07 17:48:08 -0500, James Kanze said:
On Mar 7, 10:03 pm, Pete Becker <p...@versatilecoding.com> wrote:
On 2011-03-07 16:53:50 -0500, crea said:
[...]
No, it just needs to a text string that represents the integer value in
binary. Read about strtoul.
And one that will output the integer value in binary as well.
That's a little harder:-).
Urk. strtoul goes the wrong way, of course.
#include <iostream>
const int STR_LEN=8;
typedef char bin_str[STR_LEN];
int main()
{
bin_str str1 = "1100110";
bin_str str2 = "1000011";
bin_str str3 = "0000000";
for(int x=0; x<STR_LEN; x++){
if(str1[x]=='1' && str1[x]==str2[x])
str3[x]=str1[x];
}
std::cout<< str3;
}
.... ...
const std::size_t STR_LEN=8;
.... ...
for(std::size_t x=0; x != STR_LEN; x++){
or use pointers (in lieu of iterators).
Also:
In C++ a member function is a member of class not a member of an object;
in C++ an object is simply a region of storage.
HTH.
/Leigh