Re: Logic AND between some strings

From:

"Paul" <pchristor@yahoo.co.uk>

Newsgroups:

comp.lang.c++

Date:

Wed, 9 Mar 2011 00:23:24 -0000

Message-ID:

<5Mzdp.133772$up7.72440@newsfe04.ams2>

"Leigh Johnston" <leigh@i42.co.uk> wrote in message
news:2qWdnZuNsc_qMevQnZ2dnUVZ8j6dnZ2d@giganews.com...

On 08/03/2011 21:46, Paul wrote:

"Pete Becker" <pete@versatilecoding.com> wrote in message
news:2011030808444315377-pete@versatilecodingcom...

On 2011-03-07 17:48:08 -0500, James Kanze said:

On Mar 7, 10:03 pm, Pete Becker <p...@versatilecoding.com> wrote:

On 2011-03-07 16:53:50 -0500, crea said:

[...]

No, it just needs to a text string that represents the integer value
in
binary. Read about strtoul.

And one that will output the integer value in binary as well.
That's a little harder:-).

Urk. strtoul goes the wrong way, of course.

#include <iostream>

const int STR_LEN=8;
typedef char bin_str[STR_LEN];

int main()
{
bin_str str1 = "1100110";
bin_str str2 = "1000011";
bin_str str3 = "0000000";

for(int x=0; x<STR_LEN; x++){
if(str1[x]=='1' && str1[x]==str2[x])
str3[x]=str1[x];
}

std::cout<< str3;

}

... ...
const std::size_t STR_LEN=8;

no.

... ...
for(std::size_t x=0; x != STR_LEN; x++){

no.

or use pointers (in lieu of iterators).

Also:

In C++ a member function is a member of class not a member of an object;

no.
nonstatic member functions are only invoked with an object of the class
type.
static member functions are part of a class not an object.

in C++ an object is simply a region of storage.

no.
There is no "simply"