Re: Printing non-printable characters
On 5/18/2011 3:55 AM, Alex Vinokur wrote:
Hi,
// --------------------
#include<iostream>
#include<iomanip>
int main()
{
char data[5];
data[0] = 'a';
data[1] = 5;
data[2] = 'b';
data[3] = 10;
data[4] = 0;
for (std::size_t i = 0; i< sizeof(data); i++)
{
char ch = data[i];
if (isprint(static_cast<int>(ch)) != 0)
{
std::cout<< ch;
}
else
{
std::cout<< "\\"<< std::oct<< static_cast<int>(ch)<< std::dec;
}
}
std::cout<< std::endl;
return 0;
}
// ------------------
Output:
a\5b\12\0
Is it possible to get the same or similar output without loop in the
program?
I have very little experience in that field, but for some reason it
seems to me that a custom locale could help. On the second thought, you
could define your own "translating" stream buffer around the default one
that would stuff the default with a different set of bytes if the byte
to be output fits a particular pattern (falls in a particular range,
etc.) The latter method is probably easier since you could implement a
translating buffer with the translation functor supplied at its
instantiation, static (if you implement the buffer as a template) or
dynamic (if you implement it as a class with a translating function as
its c-tor argument, for instance).
V
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