Re: Printing non-printable characters

From:

Michael Doubez <michael.doubez@free.fr>

Newsgroups:

comp.lang.c++

Date:

Wed, 18 May 2011 08:02:28 -0700 (PDT)

Message-ID:

<c51c7b24-a18a-4d0e-b26a-0861c14a14f8@e8g2000vbz.googlegroups.com>

On 18 mai, 15:59, Michael Doubez <michael.dou...@free.fr> wrote:

On 18 mai, 09:55, Alex Vinokur <alex.vino...@gmail.com> wrote:

Hi,

// --------------------
#include <iostream>
#include <iomanip>

int main()
{
        char data[5];
  data[0] = 'a';
  data[1] = 5;
  data[2] = 'b';
  data[3] = 10;
  data[4] = 0;

  for (std::size_t i = 0; i < sizeof(data); i++)
  {
        char ch = data[i];

        if (isprint(static_cast<int>(ch)) != 0)
        {
                        std::cout << ch;
                }
                else
        {
                std::cout << "\\" << std::oct << static=

_cast<int>(ch) << std::dec;

    }
  }
  std::cout << std::endl;

  return 0;

}

// ------------------

Output:
a\5b\12\0

Is it possible to get the same or similar output without loop in the
program?

[snip]

Another solution is the class wrapper:

class EscapedString
{
public:
   explicit EscapedString(char const * str )m_str(str){}
protected:
   char const * m_str;
   friend std::ostream operator<<(std::ostream & os, StringEncoder
const & s);
};
std::ostream operator<<(std::ostream & os, StringEncoder const & s)
{
for( ....
// your code here
return os;
};

And you use:
std::cout<<EscapedString(data)<<std::cout;

--
Michael