Re: Storing noncopyable but movable object in std::function

From:
Marc <marc.glisse@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Thu, 3 Nov 2011 16:50:31 -0700 (PDT)
Message-ID:
<j8un12$slf$1@news-rocq.inria.fr>
Daniel Kr?gler wrote:

unless you would be willing to standardize a type that *declares* a
copy-constructor/assignment operator (and similar for the move
operations), but might simply throw an exception "sorry, guys, my
internals just tell me that I cannot copy". This will break all static
deduction tools like std::is_copy_constructible (which say "yes, we
can"), until the runtime tells us something different. I don't think
that this would be a good idea.


I thought those static deduction tools were fairly unreliable to begin
with. I just checked on this simple example that a pair of move-only
types is reported as copy-assignable by g++, which blindly follows
the standard definition of std::pair. Actually assigning will result
in a compile-time error and not a runtime one though.

#include <utility>
#include <iostream>
#include <iomanip>
#include <type_traits>
struct A {
       A(){}
       A(A const&)=delete;
       A(A &&){}
};
int main(){
       std::cout << std::boolalpha;
       std::cout << std::is_copy_assignable<std::pair<A,A> >::value << '\n';
       std::pair<A,A> a,b;
       // b=a;
}

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