Re: Debug assertion failed in tree implementation

From:
Paavo Helde <myfirstname@osa.pri.ee>
Newsgroups:
comp.lang.c++
Date:
Sat, 05 May 2012 12:55:34 -0500
Message-ID:
<XnsA04AD4DF3D448myfirstnameosapriee@216.196.109.131>
David Kevin <davidkevin@o2.pl> wrote in
news:ca74a81a-138d-4597-bb12-8d3912db0c49@bh8g2000vbb.googlegroups.com:

Hi,
I would be grateful if somebody could explain why following code
causes assertions failures:

//#include "stdafx.h" //neccessary if you compile with VC++ 2008
#include <iostream>
#include <cstdlib>
#include <ctime>
#include <vector>
#include "stdio.h"
using namespace std;

class A {
public:
     A() {}
     A(int currentDepth, int depth) { cout << currentDepth << " " <<
     depth
<< "\n"; }
     vector<A>* vecA;
};

vector<A> recursion(int fixedDepth) {
     fixedDepth--;
     getchar();


This is a non-standard function.

     cout << "We are on level: " << fixedDepth << "\n";

     vector<A> vecA;
     int Max=rand() % 5+1;
     for(int i=0; i<Max; i++) {
          A a;
          vecA.push_back(a);
     }


This can be written more concisely:

      int Max = rand()%5 + 1;
      vector<A> vecA(Max);

     vector<A>::iterator it;
     for(it=vecA.begin(); it!=vecA.end(); it++) {
          if(fixedDepth==0) {
               if(it==vecA.end()) break;


This 'break' is never executed, the same condition has just been checked
a couple of lines above.

               it++;


Delete the above line; if you think about what 'continue' does you will
see why this is causing problems.

               continue;
          }
          it->vecA=new vector<A>;
          *it->vecA=recursion(fixedDepth);
     }
     return vecA;
};

int main()
{
     srand((unsigned)time(0));
     vector<A> a=recursion(2);
    return 0;
}


hth
Paavo

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