Re: std::bind1st making life difficult

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++
Date:
Sat, 06 May 2006 12:08:58 +0200
Message-ID:
<4c3atsF13m8i4U1@individual.net>
* pillbug:

I'm having trouble using bind1st with mem_fun1. I can't compile
the line marked below with a @@. If I use the join2 method everything
is fine, but I wind up passing string vectors by value. I would like
to use the reference passing version, or something similar.

The errors I get point the finger at binder1st::operator() being defined
as "const argument_type&" which becomes "const const string_vector&&"
when i use Joiner::join below.

Any advice would be appreciated. I use vc7.1

#include <string>
#include <vector>
#include <functional>
#include <algorithm>
#include <numeric>
#include <iostream>


Pedantic: #include <ostream> here (not that your compiler will complain).

typedef std::basic_string<char> string;


Please don't define a name that's used by the standard library; it only
sows confusion, and acts as a bug-attractor.

typedef std::vector<string> string_vector;


Good.

struct Joiner {
    string join (const string_vector& v) {
        return std::accumulate (v.begin(), v.end(), string()); }
    string join2 (string_vector v) {
        return std::accumulate (v.begin(), v.end(), string()); }
};


Is there perhaps some reason why these functions are non-const member
functions? I'll assume there is. But in the context of the code you've
shown, there's none: they should at least be const, preferably static,
or perhaps non-member.

int main (int argc, char** argv)
{
    // a 10x7 matrix of strings initialized to "Text"
    std::vector<string_vector> vv (10, string_vector (7, "Text"));

    Joiner j;
    string_vector result (vv.size());
    std::transform (vv.begin(), vv.end(),
        result.begin(),
        //std::bind1st (std::mem_fun1 (&Joiner::join), &j)); //error
        std::bind1st (std::mem_fun1 (&Joiner::join2), &j));

    std::copy (result.begin(), result.end(),
        std::ostream_iterator<string> (std::cout, "\n"));

    return 1;


That's an undefined return value, but in practice it maps to "error".
You'd want to indicate "success". Do that by omitting return, or by
returning 0 (which is the default for main), or EXIT_SUCCESS.

}


Regarding the error, try

     class JoinerFunc: public std::unary_function<string_vector, string>
     {
     private:
         Joiner* myJ;
     public:
         JoinerFunc( Joiner* j ): myJ( j ) {}
         string operator()( string_vector const& v ) const
         { return myJ->join( v ); }
     };

     int main()
     {
         // a 10x7 matrix of strings initialized to "Text"
         std::vector<string_vector> vv (10, string_vector (7, "Text"));

         Joiner j;
         string_vector result (vv.size());
         std::transform(
             vv.begin(), vv.end(), result.begin(), JoinerFunc( &j )
             );

         std::copy (result.begin(), result.end(),
             std::ostream_iterator<string> (std::cout, "\n"));
     }

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