Re: Declaring Template Classes that take Multiple Nested Templates as Parameters

From:
"mlimber" <mlimber@gmail.com>
Newsgroups:
comp.lang.c++
Date:
9 Jun 2006 13:05:06 -0700
Message-ID:
<1149883506.368476.128520@j55g2000cwa.googlegroups.com>
amparikh@gmail.com wrote:

pag...@gmail.com wrote:

Hello,

I'm having some difficulty compiling template classes as containers for
other template objects. Specifically, I have a hierarchy of template
classes that contain each other. Template class B has an instance of
template class A, which has some base type T (usually int or double).
However, the base type T is important to calculations in B, so I would
like to obtain access to the type for further variable declaration
within B. Below is a simplified version of my best attempt at the
syntax. I'm compiling under XCode 2.0 on Mac OS X version 10.4.6 using
GCC 4. Error messages have been commented in after lines in which they
occur:

//=========================================
#include <iostream>
#include <vector>

template <typename T> class A
{
   typedef T base_type;

   public:
      base_type get_item(int index)
      {
         return data_(index);
      }

   private:
      std::vector<base_type> data_;
};

template <template <typename T> class A> class B
{
   typedef T base_type; // error: 'T' does not name a type
   typedef A<base_type> Atype; // error: 'base_type' was not declared
in this scope

   public:
      base_type get_item(int index)
      {
         return data_.get_item(index);
      }

   private:
      Atype data_;

};
//=========================================

Is there any way to gain access to these nested template parameters
from within class B? Is there a better way to get this same
functionality without intimate knowledge of A's types? Am I just
making some syntax error in the template class declaration?

Thanks for the help!


The template parameter T that you have defined in the template class B
is really a template parameter for the template template parameter A.

It isnt visible outside. In many ways it is just a holder when
declaring a template template parameter and infact if you dont refer to
it again, you dont even need to have a name for that.

anyway try this.

template <typename T> class A
{
   typedef T base_type;

   public:
      base_type get_item(int index)
      {
         return data_(index);
      }

   private:
      std::vector<base_type> data_;

};

template < typename T, template <typename> class A> class B
{
   typedef T base_type; // error: 'T' does not name a type

   typedef A<base_type> Atype; // error: 'base_type' was not
declared in this scope

   public:
      base_type get_item(int index)
      {
         return data_.get_item(index);
      }
   private:
      Atype data_;
};


Or...

 template <typename T> class A
 {
 public:
   typedef T base_type; // now public

   base_type get_item(int index)
   {
     return data_(index);
   }
 private:
   std::vector<base_type> data_;
 };

 template <class A> class B
 {
   typedef typename A::base_type base_type;

 public:
    base_type get_item(int index)
    {
      return data_.get_item(index);
    }
 private:
    A data_;
 };

Cheers! --M

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