Re: debug assert error in a std::sort of vector<int>

From:
"P.J. Plauger" <pjp@dinkumware.com>
Newsgroups:
comp.lang.c++.moderated
Date:
18 Oct 2006 15:23:21 -0400
Message-ID:
<XIednXOIIKjh0qvYnZ2dnUVZ_smdnZ2d@giganews.com>
<lists@givemefish.com> wrote in message
news:1161170928.176129.21350@i3g2000cwc.googlegroups.com...

I'm getting a debug assert error when performing a sort.
The platform / compiler is Windows XP Pro / MSVC 8.0 (Professional
Edition), in debug configuration.

Here is the code fragment:

[code]
   std::vector<int> v1;

   v1.push_back(3);
   v1.push_back(4);
   v1.push_back(8);
   v1.push_back(5);
   v1.push_back(6);
   v1.push_back(7);
   v1.push_back(5);

   std::sort(v1.begin(), v1.end(), not2(std::greater<int>()));
[/code]

[I realize that I could use std::less<int> in this case, but I was
experimenting with not2.]

I get the assertion from within the sort function that says:

  Expression: invalid operator <

The code appears to work fine if I ignore the assertion. Also, the
code compiles and runs under gcc.

Am I really making an error?


Yes. Your predicate is effectively !(x < y) which is the same as
x >= y which is *not* a strict weak ordering. The debugging code
in our library detects any predicate call where pred(x, y) and
pred(y, x) are both true -- a sure sign that pred is not a strict
weak ordering.

Sometimes sort rattles around and survives being called with
a bad predicate; sometimes it gets the wrong answer; and
sometimes it stores off the end of the sorted sequence. So
just because it "appears to work fine" or "runs" does not
mean it's safe/valid code.

P.J. Plauger
Dinkumware, Ltd.
http://www.dinkumware.com

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