Re: using vector to encapulate a tree - non const copy constructors

From:
"Le Chaud Lapin" <jaibuduvin@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
16 Nov 2006 21:04:11 -0500
Message-ID:
<1163717913.402250.37410@m7g2000cwm.googlegroups.com>
terry wrote:

Repost as the original (13th Oct) did not appear on the site.

Hi, I have a problem with the way some implimentations of vector and other
stl containers refuse to use non-const contructors. My question is - is
the way they function the correct interpretation of the standard - and
if so
why.

MOTIVATION
The following data structure
class mytree: public T, protected std::vector<mytree>{};

defines a tree with an object of type T at each node (it is in top down
form where at each node, one has a value of type T, and a container of
offspring
trees).


As Ulrich pointed out, mytree is not yet anything, and there can be no
containment of something that is a nothing.

The conceptual image you have in mind, trying to make a tree by
successively "spreading" out from a node, is erroneous. You're going to
have to make a full-blow tree structure "in the raw", using internal
linkage, and encapsulate all of it in a class called "mytree".

-Le Chaud Lapin-

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