Re: std::transformation. Not calling the function object?

From:
"Daniel T." <daniel_t@earthlink.net>
Newsgroups:
comp.lang.c++.moderated
Date:
Sun, 4 Feb 2007 04:33:17 CST
Message-ID:
<daniel_t-8B0C7A.21063503022007@news.west.earthlink.net>
In article <1170529337.273151.163670@k78g2000cwa.googlegroups.com>,
  Michael.Reiland@gmail.com wrote:

it doesn't seem to be calling the function object although the
compilation depends on it. If someone could explain to me what I'm
doing incorrectly I'd appreciate it.

----------------------------
class StringToIntFuncObj
{
    public:
        int operator()(char ch)
        {
            std::cout << "HERE" << std::endl;
            //std::cout << "ch: " << ch << std::endl;
            //std::string str(my_str.substring(0,1));

            //int ret;
            //std::stringstream(str) >> ret;

            //return ret;
            return 1;
        }
    private:
};

int main(int argc, char *argv[])
{
    std::string string_rep = "12";

    std::vector<int> poly_rep(string_rep.size());
    poly_rep.resize(string_rep.size());

    StringToIntFuncObj stoi;

    std::transform(string_rep.begin(), string_rep.end(),
poly_rep.begin(),stoi);

    for( int i = 0; i < poly_rep.size(); i++)
                std::cout << poly_rep[i] << std::endl;

    return EXIT_SUCCESS;
}
----------------------------------------------------------

The output will be:
12
2

My goal is to take a string of numbers & place the digits in a vector
of ints.

I don't understand what's happening.


My output was:

HERE
HERE
1
1

int main()
{
    string input = "0123456789";
    vector<int> result;

    transform( input.begin(), input.end(), back_inserter( result ),
                               bind2nd( minus<int>(), '0' ) );
    copy( result.begin(), result.end(),
                               ostream_iterator<int>( cout, " " ) );
}

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