Re: the meaning of lvalue in C++

From:
"James Kanze" <james.kanze@gmail.com>
Newsgroups:
comp.std.c++
Date:
Tue, 13 Mar 2007 08:47:36 CST
Message-ID:
<1173773306.633931.288830@j27g2000cwj.googlegroups.com>
On Mar 10, 12:26 am, "jam" <farid.mehr...@gmail.com> wrote:

On Mar 10, 12:25 am, "restor" <akrze...@interia.pl> wrote:

Does lvalue have any useful meaning in C++? The original (i.e.: as
used in C) was that it is whatever that can be assigned a value. But
in C++ the code:

std::complex<double> Complex() { return std::complex<double>(); }
Complex() = Complex();

Is valid. Also the code:

int Integer() { return 1; }
const int& cref = Integer();
int& ref = const_cast<int&>( cref ); // is it a cast from rvalue to
lvalue???
ref = 3;

Is valid, but it is unclear (at least for me) what is 'ref'. Is it an
lvalue pointing to a temporary?
We also have non-modifiable lvalues (consts) and modifiable rvalues
like here:

ReturnObj().ModifyMe();

So what is useful in having a concept of lvalue in C++?


What is the use of an lvalue by the way?
I should say that even const objects can be lvalue:


Even in C.

struct Lvalue{
     Lvalue operator=(const Lvalue &)const{};//look at this!!

};

{
  const Lvalue L1,L2;
  L1=L2;//huh huh look at me

};

generally the only real Rvalue in C++ are literal numbers and
enumerations.


And most expressions. What's particular about class type
temporaries isn't that they aren't rvalues; it's that it's
possible, indirectly, to get their address (via the this
pointer) even though they are rvalues.

As for the "utility": I think it's largely a question of C
compatibility. Not just at the language level, but at a larger
"look and feel" level. One could easily do away with the
concept entirely, allowing things like "&(i + 3)" (with type
const int? and of course, the usual lifetime of a temporary),
but somehow, the language wouldn't feel the same.

--
James Kanze (GABI Software) email:james.kanze@gmail.com
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