Re: Simple iterator question

Hi All,

I have :

#include <iostream>
#include <list>
using std::cout;
using std::list;
using std::endl;

class MyClass {
   private:
       int myVar;
   public:
       MyClass(int v):myVar(v){};
       int getVar(){return myVar;};
       void setVar(int var){myVar = var;};
};

void someFunc(Not sure what to put here c){}

int main(){
   list<MyClass> myList;
   list<MyClass>::iterator it;

   for(int i = 0; i < 5; i++){
       MyClass element(i);
       myList.push_front(element);
   }

   for(it = myList.begin(); it != myList.end(); it++){
       if(*it.getVar() == 2){
           //someFunc(it);
       }
   }
   cout << "done" << endl;
}

(I know I have some magic numbers, please ignore these, I am just trying
to
get the iterator stuff clear in my head.)

I have two questions:
1. Why can I not access the members of MyClass using *it.memb_name()? If I
make it a list of MyClass* I can use (*it)->memb_name(), so why when I
have
a list of MyClass does *it.getVar() cause the compiler to complain thet
getVar() is undeclared?

2. How (can I?) pass the iterator to another function? What prototype
would
I use