Re: avoiding virtual call with pointer to member function

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Wed, 4 Apr 2007 17:14:18 -0400
Message-ID:
<ev14fc$vvr$1@news.datemas.de>
xtrigger303@gmail.com wrote:

Hi to all,
a newbie question. Is it possible to avoid the virtual mechanism with
pointers to members syntax the same way it's done with an explicit
call ( obj.Base::Func() )? It would be useful for something I'm
doing... check out the trivial program down here...
Thanks in advance,
Francesco

#include <iostream>

struct Base
{
virtual ~Base() {}
virtual void Do() const { std::cout << "Base\n"; }
};

struct Der : public Base
{
virtual void Do() const { std::cout << "Der\n"; }
};

int main()
{
Der obj;

obj.Base::Do(); // avoid virtual call

void ( Base::*ptrToMembFunc )() const = &Base::Do;

( obj.*ptrToMembFunc )(); // virtual call
// is there a way to avoid virtual call with pointers to member
functions
// as in the above direct call?
}


You could try forcing 'obj' into being a 'Base' by means of
'static_cast'...

V
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