Re: deleting vector elements while looping thru it

From:
"James Kanze" <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
12 Apr 2007 05:25:41 -0700
Message-ID:
<1176380741.468971.47710@q75g2000hsh.googlegroups.com>
On Apr 11, 4:50 pm, "kafe...@hotmail.com" <kafe...@hotmail.com> wrote:

What is the typical way to loop through a vector while deleting
certain elements during the loop process? The code below works, but I
am wondering if there is a better solution.

        vector<int> vTmp;
        vTmp.push_back(1);
        vTmp.push_back(2);
        vTmp.push_back(1);
        vTmp.push_back(2);
        vTmp.push_back(1);
        vTmp.push_back(1);

        for(int x=0; x<vTmp.size(); x++)
        {
                if(vTmp[x]==1)
                {
                  vTmp.erase(vTmp.begin()+x,vTmp.begin()+x+1);
                  x--; //to account for new size
                }
        }


Others have pointed out the solution using remove or remove_if,
which handles this specific case. More generally, if you're
possibly doing a number of other things, or for some other
reason prefer writing the loop yourself:

    std::vector<int>::iterator current = v.begin() ;
    while ( current != v.end() ) {
        // ...
        if ( shouldBeDeleted ) {
            current = v.erase( current ) ;
        } else {
            ++ current ;
        }
    }

can be used. (Note that in the case of vector, this is likely
to result in a lot more copying than using std::remove. If the
container is a list, however, it's probably more efficient. And
of course, unless the container is very big, and the types
expensive to copy, it generally doesn't matter.)

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James Kanze (GABI Software) email:james.kanze@gmail.com
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