Re: Templating classes

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Fri, 1 Jun 2007 16:39:02 -0400
Message-ID:
<f3q05a$m8s$1@news.datemas.de>
MathStuf wrote:

I am working on a class that will be a matrix based on a vector of
vectors. I am having trouble with the following code causing errors on
compilation:

template<class T> class MatrixBase
{
  public:
     MatrixBase()
     {
        width = 0;
        height = 0;


Those are better initialised.

        matrix.clear();


No need to clear a freshly constructed vector.

     }
     MatrixBase(const unsigned w, const unsigned h, const T &d = T())
     {
        matrix.resize(w, std::vector<T>(h, d));
        width = w;
        height = h;


Again, those are better initialised than assigned.

     }

     void AddRow(const T &d = T())
     {
        for (std::vector<T>::iterator i = matrix.begin(); i !=


'matrix.begin()' returns 'std::vector<std::vector<T> >::iterator.
You probably want to make this loop nested.

Also, 'std::vector<T>::iterator' is a dependent name. The compiler
doesn't know that it can be used where a type is expected. You need
to tell the compiler to trust you:

   for (typename std::vector<T>::iterator ...
        ^^^^^^^^

matrix.end(); ++i)
           i->push_back(d);


If you don't make this loop nested (which is fine), you might want
to review what you're pushing.

        ++height;
     }
     // More methods
  protected:
     std::vector< std::vector<T> > matrix;
     unsigned height;
     unsigned width;
};

In the AddRow method (and other, similar methods as well), it says
that it needs an ';' before i and that it's undeclared.


That's because it doesn't believe that 'std::vector<T>::iterator' is
in fact a type. Use 'typename' to tell it.

It also says
that 'height' and 'width' are undeclared.


Where?

Should I move the variable
definitions up to the top of the class or should the methods be
outside of it entirely?


Not sure what you're asking here, sorry.

V
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