Re: Oops! Comma operator is the hardest to understand in the C++ standard!

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Thu, 21 Jun 2007 20:00:50 -0400
Message-ID:
<f5f3fj$dh7$1@news.datemas.de>
Lighter wrote:

On Jun 22, 6:15 am, jg <jgu...@gmail.com> wrote:

On Jun 21, 10:19 am, Lighter <cqu...@gmail.com> wrote:

On Jun 22, 1:03 am, Markus Schoder <a3vr6dsg-use...@yahoo.de> wrote:

Since one couldn't check whether the conversion happens or not, WHY
did the C++ standard explicitly provide such a rule which doesn't
exist in the C language standard? What confused me is just the
question.


You sure can check if your C++ compiler does the lvalue-to-rvalue
conversion. Try the following code, if it crashes, it does not;
otherwise, it does.

JG
-----------------------
#include <iostream>

int main()
{
  int *pi=0;

  int x = (*pi, 10);

  std::cout << x << std::endl;
  return 0;

}- Hide quoted text -

- Show quoted text -


I tried with VS 2005. It didn't crash. That means the compiler doesn't
perform lvalue-to-rvalue conversion.


No, it doesn't mean squat. Undefined behaviour is just that, undefined.
If the compiler [by not following the Standard] actually performs the
conversion, there is no way to tell by observing the undefined behaviour
of the program above.

V
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