Re: Dereferencing (pointer to) iterator
xgngli@gmail.com wrote:
On Jun 22, 6:04 pm, Andre Kostur <nntps...@kostur.net> wrote:
"xgn...@gmail.com" <xgn...@gmail.com> wrote
innews:1182549317.833678.206870@z28g2000prd.googlegroups.com:
Suppose we have a vector:
vector<int> vec(10);
We can declare a iterator this way:
vector<int>::iterator vecItor;
and then dereference it like this:
for (vecItor = vec.begin(); vecItor != vec.end(); vecItor++)
{
cout << *vecItor << endl;
}
But how can we dereference the iterator if we declare it this way:
vector<int>::iterator* vecItor;
**vecItor.
That's a pointer-to-iterator. So you need to dereference your
pointer
part, then dereference the iterator.
Thanks guys. That makes perfect sense. However, when I run this in
Visual Studio,
vector<int> vec(10);
vector<int>::iterator* vecItor = new vector<int>::iterator();
for (*vecItor = vec.begin(); *vecItor != vec.end(); vecItor++)
... (*vecItor)++
and, REALLY, why do you need this nonsense?
{
cout << **vecItor << endl;
}
it caused debug assertion failure: vector iterators incompatible.
So I suspect there is no problem with the grammar. I just need to
search somewhere else to
find a way making VS happy.
V
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