Re: convert string into an array

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Tue, 3 Jul 2007 16:11:08 -0400
Message-ID:
<f6eags$l7m$1@news.datemas.de>
Sudzzz wrote:

On Jul 3, 3:41 pm, "Victor Bazarov" <v.Abaza...@comAcast.net> wrote:

Sudzzz wrote:

I'm trying to convert a string something like this
"{201,23,240,56,23,45,34,23}" into an array in C++
Please help.


We're happy to help. What have you done so far and what
are the problems? Read the FAQ, especially section 5.

V
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Currently I have a string "{201,23,240,56,23,45,34,23}" which changes
frequently (possibly at 3Hz). The numbers can be any number having
less than 4 digits. I want to take this string and place it in an
array so that I can use for certain computational purposes. I've
looked through different possibilities one of which would involve an
extensive string comparison, atoi(), append to array sort of
algorithm. However I realized that when we input arrays c++ accepts it
in the same form as above and then I thought whether I could simulate
c ++ input this string when asked for an array.


Yes, you can simulate C++ input, and it will involve some character
comparison, atoi (or strtol, more like it), append to array, sort of
algorithm. How do you think the compiler does that?

I don't know where to start.


Start here:

    #include <string>
    #include <vector>
    #include <cassert>

    int main() {
        std::string mystring("{201,23,240,56,23,45,34,23}");
        std::vector<int> vint;

        // write code to extract numbers from the 'mystring'
        // and place them into 'vint'

        assert(vint.size() == 8);
        assert(vint[0] == 201);
        assert(vint[1] == 23);
        assert(vint[2] == 240);
        assert(vint[3] == 56);
        assert(vint[4] == 23);
        assert(vint[5] == 45);
        assert(vint[6] == 34);
        assert(vint[7] == 23);
    }

V
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